b^2-4b-320=0

Solution for b^2-4b-320=0 equation:

Simplifying
b2 + -4b + -320 = 0

Reorder the terms:
-320 + -4b + b2 = 0

Solving
-320 + -4b + b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(-16 + -1b)(20 + -1b) = 0

Subproblem 1
Set the factor '(-16 + -1b)' equal to zero and attempt to solve:

Simplifying
-16 + -1b = 0

Solving
-16 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '16' to each side of the equation.
-16 + 16 + -1b = 0 + 16

Combine like terms: -16 + 16 = 0
0 + -1b = 0 + 16
-1b = 0 + 16

Combine like terms: 0 + 16 = 16
-1b = 16

Divide each side by '-1'.
b = -16

Simplifying
b = -16
Subproblem 2
Set the factor '(20 + -1b)' equal to zero and attempt to solve:

Simplifying
20 + -1b = 0

Solving
20 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-20' to each side of the equation.
20 + -20 + -1b = 0 + -20

Combine like terms: 20 + -20 = 0
0 + -1b = 0 + -20
-1b = 0 + -20

Combine like terms: 0 + -20 = -20
-1b = -20

Divide each side by '-1'.
b = 20

Simplifying
b = 20
Solution
b = {-16, 20}